Question

a force of 1 N acts on a body at rest and mass 1 kg .during this time the body attains a velocity of 30 m/s .the time for which the force acts on a body is​

Answer 1

Force = mass x acceleration

1N = 1kg x a

a = 1m/s^2

Now,

acceleration= (v -u)/ t

Where,

u = initial velocity = 0 (rest)

v = final velocity = 30m/s

t = time (sec) for which force acts ( since acceleration is always produced by unbalanced force)

Now,

1 m/s^2 = 30 m/ t

t = 30 sec

Hence,

Force acted for 30 second

Answer 2

Answer:

Time, t = 30 seconds

Explanation:

Given;-

       Force, F = 1 N

       Mass, m = 1 kg

   Velocity, v = 30 m/s

Then;-

∵      F = p/t [where, p = momentum, f = force, t= time]

∴     1 = m×v/ t [since, p = mv]

         1 = 1 × 30 / t

         t = 30 seconds.

Hence, the time for which the force acts on a body is 30 seconds.

Hope it helps! ;-))