Question

A force of 10.5 N acts on a particle along a direction making an angle 37° with the vertical find the component of the force in the verticle direction

Answer 1

Answer:

Explanation:

Aloha !

Given, f=10.5& angle=37°

Component in vertical = fcostheta°

= fcos37

=10.5*4/5

=8.4N

Thank you

@ Twilight Astro ✌️☺️❤️

Answer 2

Answer:

Explanation:

Hola mate,

the component of the force in the verticle direction= fcos theta

=10.5cos37°

=10.5×4÷5

=8.4 Newton

Hope it will help you