Question

A force of (10 i -­ 3 j + 6k) N acts on a body of mass 100 g and displaces it from m to (6 i ­+ 5 j - 3k) m to (10 i - 2 j + 7 k)m. The work done is

Answer 1

Answer:

Assuming positions given were in meters, work is 121 Joules.

Step-by-step explanation:

Work equals the dot product of force and displacement. W=F∙d

Force is given as 10i−3j+6k

Displacement is calculated from the final position minus the initial position.

d=(10i−2j+7k)−(6i+5j−3k)=4i−7j+10k

To learn how to calculate the dot product, use:

W=(10i−3j+6k)∙(4i−7j+10k)

W=(10∗4)+((−3)∗(−7))+(6∗10)=40+21+60=121

Assuming positions given were in meters, work is 121 Joules.

mark me as a brainliest