Question

A force of 10 kgf is applied for 0.1 s on a body of mass 100g initially at rest. calculate the momentum acquired by the body andbdistance travelled by the body in 0.1s.

Answer 1

1)Force=10kgf=10*10=100N Weight=100g=0.1kg Acceleration =F/m=100/0.1=1000m/s^2 Velocity after 0.1s V= u+at V=0+1000*0.1 V=100m/s Momentum=P=mv=0.1*100=10Ns 2) Using S=ut+1/2at^2 S=0+1/2*1000*(0.1)^2 S=5m

Answer 2

Answer:

Force=10kgf=10*10=100N

Weight=100g=0.1kg

Acceleration =F/m=100/0.1=1000m/s^2

Velocity after 0.1s V= u+at V=0+1000*0.1 V=100m/s Momentum=P=mv=0.1*100=10Ns

2) Using S=ut+1/2at^2 S=0+1/2*1000*(0.1)^2 S=5m

Explanation: