A force of 10 N act for 20 second on a body of mass 2 kg initially at rest calculate the energy required by the body and the work done by the applied force
Answers
Answer:
Explanation: therefore, 10,000J is the energy required by the body.
Explanation:
Force = mass × acceleration
F=10N
m=2kg
then,
a=
m
F
=
2
10
=5m/s
2
(i) Now,
u=0
t=3sec
v=u+at=0+3×5=15m/s
(ii)Initial momentum=mu=2×0=0
Final momentum=mv=2×15=30kg−m/s
Change in momentum=Final momentum - Initial momentum
=30−0=30kg−m/s
hope it help u
Answer:
F = 10N
mass = 2kg
F = ma
a = F / m = 20 / 2 = 5m/s²
acceleration (a) = 5m/s²
time (t) = 20s
initial velocity (u) = 0
displacement (s) = ut + at²/2
s = 0 + 5×20² / 2
s= 5 × 20 × 20/2
s = 5 × 20 × 10
s = 1000m
Work done = F × s
= 10×1000
= 10000j
v = u + at
v = 0 + 5×20
v = 100m/s
Kinetic energy = 1/2mv²
= 1/2 × 2 × 100 × 100
= 10000joules