Question

A force of 10 N acting on a particle increases its velocity from 15 m/s to19 m/s in 2 s. The mass of the
particle is​

Answer 1

Answer:

Given:

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▪︎Force(f) = 10N

▪︎Initial velocity(u) = 15m/s

▪︎Final velocity(v) = 19m/s

▪︎Time(t) = 2s

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To Find:

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▪︎Mass of the particle(m)

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Solution:

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Acceleration(a)

= $\frac{Change\ \ in\ \ velocity}{Time}$

= $\frac{v-u}{t}$

= $\frac{19-15}{2}$

= $\frac{4}{2}$

Hence, Acceleration = 2m/s²

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As we know,

$\boxed{\fcolorbox{pink}{red}{Force = mass × acceleration}}$

According to given conditions,

F = m × a

= 10N = m × 2

= m = 10÷2

= m = 5kg.

Hence, Mass of particle is 5 kg.

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Points to be remembered:

• Acceleration = change in velocity ÷ time
• Force = mass × acceleration

Answer 2

Answer:

Given:

⠀⠀⠀⠀⠀⠀⠀⠀⠀

▪︎Force(f) = 10N

▪︎Initial velocity(u) = 15m/s

▪︎Final velocity(v) = 19m/s

▪︎Time(t) = 2s

⠀⠀⠀⠀⠀⠀⠀⠀

To Find:

⠀⠀⠀⠀⠀⠀⠀⠀⠀

▪︎Mass of the particle(m)

⠀⠀⠀⠀⠀⠀⠀⠀

Solution:

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Acceleration(a)

=  

=  

=  

=  

Hence, Acceleration = 2m/s²

⠀⠀⠀⠀⠀⠀⠀⠀

As we know,

According to given conditions,

F = m × a

= 10N = m × 2

= m = 10÷2

= m = 5kg.

Hence, Mass of particle is 5 kg.

⠀⠀⠀⠀⠀⠀⠀⠀

Points to be remembered:

Acceleration = change in velocity ÷ time

Force = mass × acceleration