A force of 10 N acts for 20 second on a body of mass 2 kg initially at rest. Calculate the energy required by the body and the work done by the applied force.
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Answered by
2
"Answer:
1000J is the answer
Explanation:
F/m= a= 5m/s²
u=0 , t=20s
v= 5m/s² * 20 s
v= 100m/s
Change in KE = KEf-KEi
(KEi = 0 as it was initially at rest )
so change in KE= 1/2 * 2kg * 10000 m²/s²
so change in KE = 10000kgm²/s² = 10000J
but we Know Work done by all forces = change in KE = 1000J
"
Answered by
1
Answer:
F = 10N
mass = 2kg
F = ma
a = F / m = 20 / 2 = 5m/s²
acceleration (a) = 5m/s²
time (t) = 20s
initial velocity (u) = 0
displacement (s) = ut + at²/2
s = 0 + 5×20² / 2
s= 5 × 20 × 20/2
s = 5 × 20 × 10
s = 1000m
Work done = F × s
= 10×1000
= 10000j
v = u + at
v = 0 + 5×20
v = 100m/s
Kinetic energy = 1/2mv²
= 1/2 × 2 × 100 × 100
= 10000joules
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