A force of 10 N acts for 20 second on a body of mass 2 kg initially at rest. Calculate the energy required
by the body and the work done by the applied force.
Answers
Answered by
18
Answer:
U=0m/s
F=ma
a=F÷m
So,a=10÷1=10
S=ut+1/2 at×t
=1/2 ×10×16
=80
W=FS
10×80
=800J
Answered by
43
Answer:
F = 10N
mass = 2kg
F = ma
a = F / m = 20 / 2 = 5m/s²
acceleration (a) = 5m/s²
time (t) = 20s
initial velocity (u) = 0
displacement (s) = ut + at²/2
s = 0 + 5×20² / 2
s= 5 × 20 × 20/2
s = 5 × 20 × 10
s = 1000m
Work done = F × s
= 10×1000
= 10000j
v = u + at
v = 0 + 5×20
v = 100m/s
Kinetic energy = 1/2mv²
= 1/2 × 2 × 100 × 100
= 10000joules
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