Physics, asked by premshirodkar23, 5 hours ago

A force of 10 N acts for 20 second on a body of mass 2 kg initially at rest. Calculate the energy required by the body and the work done by the applied force.

Answers

Answered by vivaanlal044
1

Answer:

Explanation: therefore, 10,000J is the energy required by the body.

Answered by Anonymous
2

Explanation:

F=m × d/t^2

so d= Ft^2/m

work= F×Ft^2/m

10×10 ×20×20/2= 20000 joule

Now by work energy theorem

Kinetic energy= 20000 joule

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