Science, asked by ashok888, 9 months ago

A force of 10 N acts on a 10 kg body initially at rest. The work
done by the force during the first 5 second and 5th second of
motion of body is. (in joule)
a. 3, 1.5
b. 9,4
c. 11.5,5
d. 125, 45​

Answers

Answered by vaibhav3234
0

Answer:

Brainly.in

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Secondary School Physics 5 points

A force of 5Newton acts on a 15kg body initially at rest. compute the work done by the force in a) the first, b) the second, and) the third seconds.and d) the instantaneous power due to the the force at the end of the third second.

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Me · Beginner

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resonance

resonance Ambitious

A=5/15=1/3m/s^2. _(1)

Work=F.x

a)in first second , dis placement=1/2 × a × t^2

=1/6 m

so , Work=F.x=5/6 Joule. (ANS)

b)s=1/2 at^2= 2/3 m

in 2nd second , displacement is 2/3-1/6=1/2m

so , W=5×1/2=2.5joule

c)s=1/2 at^2= 3/2 m

in 3rd second , displacement is 3/2-2/3=5/6m

so , W=5×5/6=4.17joule

(D)at the end of 3rd second ,

v=u+at

=0×(1/3)×3

=1m/s

Power=F.v

=5×1

=5J/s

I hope you are satisfied with my solution

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