Question

A force of 10 N acts on a body of 2 kg for 3 seconds. Find the kinetic energy acquired by the body in 3 seconds.​

Answer 1

F= ma

so, a= f/m

       = 10/2

       = 5 m/s²

u= 0

a= (v-u)/t

⇒at = v-u

⇒at+u=v

⇒v=at+u

⇒v=5*3+0

⇒v= 15 m/s

K.E. = 1/2(mv²)

      = (1/2*(2*15*15)

      = 15*15

      = 225 joule.

So, the energy applied in one second is 225 J

So, the total energy applied in 3 seconds = (225*3) J

                                                                     = 675 J.

Answer 2

$\huge\bold\purple{Bonjour!!}$

$\huge\mathfrak{Answer:-}$

⏩ Here, F= 10 N, m= 2 kg, t= 3s

We know that , Acceleration, a= F/m

= 10/2 = 5 m/s²

Velocity of the body after 3s,

v= u + at

= 0 + 5 × 3 = 15 m/s

Therefore,

K.E. of the body after 3:-

K.E= 1/2 mv²

= 1/2 × 2 × (15)² = 225 J. Ans.

✔✔✔✔✔✔✔

Hope it helps...:-)

⭐❤✨♥⭐❤✨♥⭐

Be Brainly..✌✌✌

♣ WALKER ♠