Question

A force of 10 N acts on a body of mass 1 kg for 2 sec to a distance if 10 m the rate of change of momentum

Answer 1

❥︎ANSWER

Start with f = m*a, so a = f/m

f = 10 N = 10 newtons m = 1 kg so a = 10 m/s^2

If it started from zero, its end velocity is v * t = 50 m/s

As momentum = m*v its momentum would be

Now, let’s start with distance = v*t or distance = average velocity times time so

10m = Va * 5 and Va Average velocity = 10/5 m/s = 2 m/s

It started from zero, so its final velocity would be 4 m/s

and its momentum would be 4 kg.m/s

Now let’s start with distance s = u*t + 1/2 a * t^2

Assuming u = 0 m/s s = 1/2 * a * t^2 and 10 = 1/2* a * 5^2

so a = 20/25 = 0.8 m/s^2

❥︎THANKS

I hope it will help you.