Question

A force of 10 N acts on a body of mass 2 kg for
3 s, initially at rest. Calculate the velocity
acquired by the body, and it change in momentum
of the body​

Answer 1

Explanation:

Step-by-step explanation:

$\huge\fcolorbox{blue}{green}{Given}$

F=10N

m=2kg

$\huge\fcolorbox{blue}{green}{Formulas used}$

Force = mass × acceleration.

• a = f / m

• 10 / 2

• 5ms^2

➣ v = u + at

$\huge\fcolorbox{blue}{green}{Solution}$

➣ Now,

➣ u = 0

➣ t = 3sec

➣ v = u + at

➣ 0 + 3 × 5 = 15m/s

➣ Initial momentum = mu = 2 × 0 = 0

➣ Final momentum = mv = 2 × 15 = 30 kg −m/s

➣ Change in momentum.

➣ Final momentum - Initial momentum

➣ 30 − 0 = 30kg − m/s