A force of 10 N acts on a body of mass 2 kg for 3 s, initially at rest. Calculate the 1. Velocity acquired by the body
2. Change in momentum of the body
Answers
Answered by
2
U=0
T=3s
F=10N
M=2kg
F=ma
10=2*a
10/2=a
5m/s square =a
a=v-u/t
5=v-0/3
5*3=v
15=v
Change in momentum =M*v
2*15
30kgm/s
T=3s
F=10N
M=2kg
F=ma
10=2*a
10/2=a
5m/s square =a
a=v-u/t
5=v-0/3
5*3=v
15=v
Change in momentum =M*v
2*15
30kgm/s
INSENSION:
absolutely correct:-)
Similar questions