Question

A force of 10 N acts on a body of mass 2 kg for 3 seconds, initially at rest, find: (i) The velocity acquired by the body (ii) Change in momentum of the body ​

Answer 1

Answer:

Force = mass× acceleration

F =10 N

mass = 2 kg

a = F/m = 10/2 = 5 m/s²

i)now, u = 0

t = 3 sec

v = u + at = 0 + 3×5 = 15 m/s

ii) initial momentum = mu = 2×0 =0

final momentum = mv = 2×15 = 30 kg m/s

change in momentum = final momentum - initial momentum 

                                   = 30 -0 = 30 kg m/s

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Answer 2

Answer:

( i ) velocity acquired by the body at the end of 3 seconds =>  v = 15 $ms^{-1}$

( ii ) change in momentum of the body => 30 $kgms^{-1}$

Explanation:

given:

F = 10 N

m = 2 kg

t = 3 s

initial velocity => u = 0

according to Newton's Second Law,

F = ma

10 = 2 * a

a = 5 $ms^{-2}$

we know that,

a = v/t

5 = v/3

( i ) v = 15 $ms^{-1}$

( ii ) change in momentum = final momentum - initial momentum

                                            = mv - mu

                                            = 2*15 - 0

                                           = 30 $kgms^{-1}$

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