Question

A force of 10 N acts on a body of mass 2 kg for 3 seconds, initially at rest calculate - i. acceleration on the body​

Answer 1

Answer:

Force(F) = 10N

Mass(M)= 2kg

Time(t) = 3sec

Initial velocity (u) = 0 m/s

From the first equation of motion,

$a= v×u/t$

Then,

or

$v=at+u$

$v= (5)(3)+0= 15 m/s^-1$

Thus,

$a= v×u/t$

$a= (15)(0)÷3=0 \: m/s {}^{2}$

Hope it helps you!

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Answer 2

Let v be the final velocity acquired. From Newton's second law, F = ma. Or, a = F/m = 10/2 = 5 ms-2.