Question

A force of 10 N acts on a body of mass 2 kg for 3s, initially at rest. Calculate i) The velocity acquired by the body ii) Change in momentum of the body

Answer 1

Answer:

30

explanation-

ANSWER

Force = mass × acceleration

F=10N

m=2kg

then,

a=

m

F

=

2

10

=5m/s

2

(i) Now,

u=0

t=3sec

v=u+at=0+3×5=15m/s

(ii)Initialmomentum=mu=2×0=0

Finalmomentum=mv=2×15=30kg−m/s

Change in momentum=Final momentum - Initial momentum

=30−0=30kg−m/s

Answer 2

Answer:

30 m/s

Explanation:

I hope it helps you