Question

A force of 10 N acts on a body to displace 5m then the work done is​

Answer 1

Answer:

$\boxed{\mathfrak{Work \ done \ (W) = 50 \ J}}$

Given:

Force (F) = 10 N

Displacement (d) = 5 m

To Find:

Work done (W)

Explanation:

Work done by the force is defined as the product of component of the force in the direction of the displacement and the magnitude of the displacement.

$\boxed{ \bold{W = Fd \: cos \theta }}$

As in the given question force is acting along the displacement.

So,

$\sf \theta = 0^{\circ}$

Now, by substituting values of F, d & $\sf \theta$ in the formula we get:

$\sf \implies W = 10 \times 5 \times cos \: 0 ^{ \circ} \\ \\ \sf \implies W = 50 \times 1 \\ \\ \sf \implies W = 50 \: J$

$\therefore$

Work done (W) = 50 J

Answer 2

Explanation:

$work = force \: \times displacement$

Force = 10N

Displacement = 5m

Work = Force ×displacement

= 10×5 Nm

=50 Nm or Joule (J)