a force of 10 N acts on a mass 2 kg .find out its velocity after 5 seconds .is the body were initialy at rest
Answers
Answered by
1
given u=0
f=10N
m=2kg
time = 5 seconds.
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to find - final velocity.
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calculation
F= Ma
10=2a
so, a=10/2=> 5m/s^2.
v=u+at
v= 0+ 5(5)
v=25m/s
Anonymous:
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Answered by
3
here is your and dear
F=ma
so 10N= 2kg×a
a=10N/2kg
=5ms^-2
we know
a=change in velocity / time taken 5
initial velocity =0.
final velocity = 5
a=v-0/5
we know a=5ms^-2
so
5=v/5
v=5×5=25ms^-1
F=ma
so 10N= 2kg×a
a=10N/2kg
=5ms^-2
we know
a=change in velocity / time taken 5
initial velocity =0.
final velocity = 5
a=v-0/5
we know a=5ms^-2
so
5=v/5
v=5×5=25ms^-1
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