Question

A force of 10 N displaces a body by a distance of 3 m at an angle 60° to its own direction. Find the amount of work done.

Answer 1

F=10N,S=2m,θ=60

0

So, Work=F×Scosθ=10×2cos60

0

=10×2×

2

1

=10J

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Answer 2

Answer:

F=10N,S=2m,θ=60

0

So, Work=F×Scosθ=10×2cos60

0

=10×2×

2

1

=10J

Step-by-step explanation:

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