Question

A force of 10 N displaces a body of mass 2 Kg through a distance of 5 m in a direction at an

angle of 60° from the direction of force. Calculate the work done.​

Answer 1

Answer:

Work done in fruit case =F.S.cosθ=10×2×cos6010J

Work done in second case is same as 10J=FScosθ⇒F×2×cos30=10F=310N

Explanation:

Hope it helps you