Question

A force of 10 N displaces a body of mass 2 Kg through a distance of 5 m in a direction at an

angle of 60° from the direction of force. Calculate the work done.
​

Answer 1

Answer:

F=10N,S=2m,θ=60

0

So, Work=F×Scosθ=10×2cos60

0

=10×2×

2

1

=10J