Question

A force of 10 N gives a mass M1, an acceleration of 2m/s^2 and a mass m2, an acceleration of 4m/s^2. what acceleration would it give if both the masses are tied together?
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Answer 1

Answer:

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Using Newton's second law,

$f = m \: a$

$5 = m1 \times 10$

$m1 = \frac{5}{10} = 0.5kg$

And,

$5 = m2 \times 20$

$m2 = \frac{5}{20} = 0.25kg$

$total \: mass = 0.5 + 0.25 = 0.75kg$

Now as per question

Let common acceleration is a,

$f = (m1 + m2) \times a$

$5 = 0.75 \times a$

$a = \frac{5}{0.75} = \frac{500}{75}$

$= 6.67m/s {}^{2}$

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Answer 2

Explanation:

• Force(F) = Mass(M) * Acceleration(A)

Given: F = 10N

$a1 = 2 \frac{m}{ {s}^{2} } \\ a2 = 4 \frac{m}{ {s}^{2} }$

1. m1 = F/a1

= 10/2

= 5kg

2. m2 = F/a2

=10/4

= 2.5kg

• Now, with same force and adding both mass the acceleration would be;

A = F/ m1 + m2

= 10/5+2.5

= 10/7.5

$= 1.333 \frac{m}{ {s}^{2} }$