Question

a force of 10 N is applied on the body for 6 seconds what will be the magnitude of impulse ? 11th class​

Answer 1

Answer:

Correct option is A)

Here, F=10N,t=3μs

=3×10

−6

s;

M=5g=5×10

−3

kg

Now, impulse =Ft=10×3×10

−6

=3×10

−5

Ns

Also, impulse = change in momentum

=Mv

2

−Mv

1

=M(v

2

−v

1

)

∴(v

2

−v

1

)=

M

impulse

=

5×10

−3

3×10

−5

=6×10

−3

ms

−1