Question

A force of 10 N is required to move a conducting loop through a non uniform magnetic field at 2m/s . The rate of production of electrical energy?

Answer 1

Hey dear,
Moving non-conducting loop in magnetic field produces electromagnetic energy.

◆ Answer-
dE/dt = 20 Watt

◆ Explaination-
# Given-
F = 10 N
v = 2 m/s

# Solution-
Rate of production of electric energy is -
dE/dt = Fv
dE/dt = 10 × 2
dE/dt = 20 Watt

Therefore, rate of production of electric energy is 20 watt.

Hope it helps...

Answer 2

Answer:

ans 20 watt

Explanation:

dE/dt =U =F×v