Question

A force of 10 n is required to open a nut by using wrench of length 25 CM. What force is needed to open it by the the wrench 20 cm

Answer 1

Answer:

Force needed to open with wrench 20 cm = 12.5 N

Explanation:

Given :

For wrech of length 25 cm

F₁ = 10 N        arm length  r₁ = 25 cm = 0.25 m

Torque required to open the nut τ= F₁ x r₁ = 10 x 0.25 = 2.5 Nm

Torque remains same

For wrench of length 20 cm : r = 0.2 m

τ = F₂ x r₂

2.5 = F₂ x 0.2

∴ F₂ = 2.5/0.2 = 12.5 N

Force needed to open with wrench 20 cm = 12.5 N

Short Cut :

10 x 25 = F x 20 ⇒ F = 12.5 N