a force of 10 N pulls a trolley of mass 5 kg through a distance of 6 m what is the gain in kinetic energy of the trolley?
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work done = mass ×acceleration×distance
force=m×a
mass=5kg
F=10N
10 = 5×a
a =2 m/s^2
K.E=5×2×6
=60 J
force=m×a
mass=5kg
F=10N
10 = 5×a
a =2 m/s^2
K.E=5×2×6
=60 J
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