Question

a force of 10 Newton act on a body of mass 2 kg for 3 seconds initially at stage the velocity acquired by the body

Answer 1

Force = mass× acceleration
F =10 N
mass = 2 kg
a = F/m = 10/2 = 5 m/s²
i)now, u = 0
t = 3 sec
v = u + at = 0 + 3×5 = 15 m/s
ii) initial momentum = mu = 2×0 =0
final momentum = mv = 2×15 = 30 kg m/s
change in momentum = final momentum - initial momentum 
                                   = 30 -0 = 30 kg m/s

Answer 2

$\large\blue{heya mate!!}$

Force = 20 N

Mass = 20 kg

From Newton's second law

Acceleration = Force / Mass

= 20 N / (20 kg)

= 1 m/s²

Now, use equation of motion

v = u + at

Where

v = Velocity after time "t'

u = Velocity when "t = 0"

a = Acceleration of body

t = Time taken for the body to change its velocity from "u" to "v"

t = (v - u)/a

= (100 m/s - 0 m/s) / (1 m/s²)

= 100 s