Question

A force of 10 newton acts on a body at rest having mass 1 kg, the distance covered is 5m. What is the average velocity during this time​

Answer 1

Answer:

sorry for the origin of state for the origin

Answer 2

Force, F = 10N

Mass, m = 5Kg

Force,

F = ma

a = 2m/s²

Work done, W=F.ds

In first second, displacement,

s = 1/2 at²

s = 1/2 x 1 x 2

s = 1m

So, work done,W = 10 × 1 = 10J

In second second, s = 1/2 x 1 x 2 = 4m

So the displacement is 4 - 1 = 3m

Hence work done in 2 sec is

W = 10 x 3

W = 30 Joule