a force of 10 Newton acts on a body for 3 microseconds calculate the impulse if mass of the body is 5 g
calculate change of velocity
Answers
Answered by
10
F=ma
F= mv/t
Mv= impulse
So impulse = f*t= 10 * 3 * 10^-6 = 3*10^-5 Ns
Now v = impulse/mass
V= (3*10^-5)/(5*10^-3)
= 3/500
= 0.006 m/s
F= mv/t
Mv= impulse
So impulse = f*t= 10 * 3 * 10^-6 = 3*10^-5 Ns
Now v = impulse/mass
V= (3*10^-5)/(5*10^-3)
= 3/500
= 0.006 m/s
Answered by
3
Answer:
Explanation:
Here,
F = 10N,t=3μs
=3×10⁻ ⁶ s;
M=5g=5×10 ⁻³ kg
Now, impulse =Ft=10×3×10⁻⁶
=3×10⁻⁵ Ns
Also, impulse = change in momentum
=Mv₂-Mv₁
=M(v₂ - v₁)
∴(v₂-v₁)= impulse/m
=3×10⁻⁵/ 5×10⁻³
= 6×10⁻³ ms⁻¹
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