Physics, asked by cimt, 1 year ago

a force of 10 Newton acts on a body for 3 microseconds calculate the impulse if mass of the body is 5 g
calculate change of velocity

Answers

Answered by IITJEEmath
10
F=ma
F= mv/t
Mv= impulse
So impulse = f*t= 10 * 3 * 10^-6 = 3*10^-5 Ns

Now v = impulse/mass
V= (3*10^-5)/(5*10^-3)
= 3/500
= 0.006 m/s
Answered by raviprasadm
3

Answer:

Explanation:

Here,

F = 10N,t=3μs

=3×10⁻  ⁶  s;

M=5g=5×10  ⁻³ kg

Now, impulse =Ft=10×3×10⁻⁶  

=3×10⁻⁵   Ns

Also, impulse = change in momentum

=Mv₂-Mv₁

=M(v₂ -  v₁)

∴(v₂-v₁)= impulse/m

=3×10⁻⁵/ 5×10⁻³

= 6×10⁻³ ms⁻¹

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