A force of 10 Newton acts on a body of mass 2 kg for 3 seconds initially at rest then the velocity acquired by the body is??
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Answered by
6
Force = mass × acceleration of body
10 N = 2kg × acceleration
acceleration ( a ) = 5 m/s²
use ,
v = u + at
given,
u = 0
a = 5 m/s²
t = 3 sec
V = 0 + 5 × 3 = 15m/s
10 N = 2kg × acceleration
acceleration ( a ) = 5 m/s²
use ,
v = u + at
given,
u = 0
a = 5 m/s²
t = 3 sec
V = 0 + 5 × 3 = 15m/s
Answered by
2
HI there !!
Mass = m = 2 kg
Force = F = 10 N
Time = t = 3 sec
Acceleration = a
Force = ma
10 = 2a
a = 10/2
a = 5 m/s²
As the body is at rest ,
initial velocity = u = 0 m/s
Final velocity = v
Equation of Motion :
v = u + at
v = 0 + 5 x 3
v = 15 m/s
Velocity acquired by the body = 15 m/s
Mass = m = 2 kg
Force = F = 10 N
Time = t = 3 sec
Acceleration = a
Force = ma
10 = 2a
a = 10/2
a = 5 m/s²
As the body is at rest ,
initial velocity = u = 0 m/s
Final velocity = v
Equation of Motion :
v = u + at
v = 0 + 5 x 3
v = 15 m/s
Velocity acquired by the body = 15 m/s
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