Question

a force of 10 Newton acts on a body of mass 2 kg for 3 seconds initially at rest calculate the velocity attained by the body and change in momentum of the body

Answer 1

force=m×a=m×v-u/t
10=2(v)/3. ( u=0)
v=15

Answer 2

a=f/m
a=10/2=5m/s2
v=u+at
v=0+5*3
v=15m/s