a force of 10 Newton acts on a body of mass 2 kg for 3 second initially at rest calculate the velocity acquired by the body and second the change in momentum of the body in friends please help for the exam time
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5
F = 10 N
m = 2 kg
t = 3 s
u = 0
F = m ( v -u ) /t
10 = 2 ( v - 0 ) /3
10 = 2v /3
30 = 2v
v = 15 m/s
p(f) = mv = 2 x 15 = 30 kg m/s
p(I) = mu = 2 x 0 = 0 kg m/s
p(f) - p(I) = 30 - 0 = 30 kg m/s
m = 2 kg
t = 3 s
u = 0
F = m ( v -u ) /t
10 = 2 ( v - 0 ) /3
10 = 2v /3
30 = 2v
v = 15 m/s
p(f) = mv = 2 x 15 = 30 kg m/s
p(I) = mu = 2 x 0 = 0 kg m/s
p(f) - p(I) = 30 - 0 = 30 kg m/s
tejaswa2:
ready to help another time friend bye
Answered by
4
Force = F = 10N
Mass = m = 2kg.
Acceleration = a
Initial velocity = u = 0
Final velocity = v
Time = t = 3 seconds
F = m × a
10 = 2 × a
a = 10/2 = 5
a =( v-u)/t
5 = (v-0)/ 3
v = 5×3=15.
Momentum = m×v = 2 × 15 = 30
Hope it helps !!! ;-)
Mass = m = 2kg.
Acceleration = a
Initial velocity = u = 0
Final velocity = v
Time = t = 3 seconds
F = m × a
10 = 2 × a
a = 10/2 = 5
a =( v-u)/t
5 = (v-0)/ 3
v = 5×3=15.
Momentum = m×v = 2 × 15 = 30
Hope it helps !!! ;-)
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