Question

a force of 10 Newton acts on a body of mass 2 kg for 3 second initially at rest calculate the velocity acquired by the body and second the change in momentum of the body in friends please help for the exam time

Answer 1

F = 10 N 

m = 2 kg 

t = 3 s 

u = 0 

F = m ( v -u ) /t 

10 = 2 ( v - 0 ) /3 

10 = 2v /3 

30 = 2v 

v = 15 m/s 

p(f) = mv = 2 x 15 = 30 kg m/s 

p(I) = mu = 2 x 0 = 0 kg m/s 

p(f) - p(I) = 30 - 0 = 30 kg m/s 

Answer 2

Force = F = 10N
Mass = m = 2kg.
Acceleration = a
Initial velocity = u = 0
Final velocity = v
Time = t = 3 seconds

F = m × a
10 = 2 × a
a = 10/2 = 5

a =( v-u)/t
5 = (v-0)/ 3
v = 5×3=15.

Momentum = m×v = 2 × 15 = 30

Hope it helps !!! ;-)