a force of 10 Newton acts on a body of mass 2 kg for 3 seconds initially at rest calculate the change in momentum of the body
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3
F=ma
10=2a
a=5m/s^2
now
v=u+at
=5×3
=15m/s
p=mv
=15×2
=30
10=2a
a=5m/s^2
now
v=u+at
=5×3
=15m/s
p=mv
=15×2
=30
Answered by
1
acceleration is 5,velocity is 15,p=30
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