Question

a force of 10 Newton acts on a body of mass 5 kg for one second then the rate of change of momentum will be ​

Answer 1

$force = 10n \\ mass = 5kg \\ f = m \times a \\ a = \frac{f}{m} = \frac{10}{5 } = 2m {s}^{2 } \\ rate \: of \: change \: in \: momentum = \frac{m(v - u)}{t } = m \times a \\ = 5kg \times 2 {ms}^{2} \\ = 10 {ms}^{2}$