Question

a force of 10 Newton acts on an object and shows a displacement of 7 minut the direction of force what is the work done in this case​

Answer 1

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Given:—

• Force (F) = 10N
• Displacement (s) = 7m
• Since Displacement is in the direction of motion. So, angle (θ) = 0°

To find:—

• Work done(W)

Solution:—

We know that,

⠀⠀⠀⠀⠀⠀Work done = Fscosθ

⠀⠀⠀⠀⟹ Work done = (10)(7)cos0°

⠀⠀⠀⠀⟹ Work done = (10)(7)(1)

⠀⠀⠀⠀⟹ Work done = 70 J

So, the required work done is 70 joule.

Answer 2

Given:—

Force (F) = 10N

Displacement (s) = 7m

Since Displacement is in the direction of motion. So, angle (θ) = 0°

To find:—

Work done(W)

Solution:—

We know that,

⠀⠀⠀⠀⠀⠀Work done = Fscosθ

⠀⠀⠀⠀⟹ Work done = (10)(7)cos0°

⠀⠀⠀⠀⟹ Work done = (10)(7)(1)

⠀⠀⠀⠀⟹ Work done = 70 J

So, the required work done is 70 joule.