A force of 10 newton is applied to a statinary mass of 25kg. the work done in the 1st second is given by?
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Given,
F=10n
m=25kg
F = ma
a=m/F
= 25/10
= 2.5
W=ma
= 25x2.5
= 62.5
F=10n
m=25kg
F = ma
a=m/F
= 25/10
= 2.5
W=ma
= 25x2.5
= 62.5
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