Question

A force of 100 g wt is required to pull a body weighing I kg over ice. What is the co-
efficient of friction? g = 9.8m/s²​

Answer 1

Answer:

μ= 1/9.8=0.1

Explanation:

force=100g wt= 1N

weight of body =1 x 9.8 = 9.8N

friction=μΝ=μmg

putting the values

1 = μ x 9.8

μ = 1/9.8=0.1

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