Question

A FORCE OF 100 N acts on a body of mass 20 kg initially at rest for 5 sec . determine
(a) acceleration
(b) final velocity attained by it
(c) distance covered by it

Answer 1

The answers and calculations is in the image.
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Answer 2

Given,

Force = 100 N

Mass of the body = 20 kg

Time = 5 seconds

To Find,

(a) Acceleration

(b) Final velocity attained by it

(c) Distance covered by it

Solution,

We can solve the question using the following steps:

(a) Acceleration

We know, $F = ma$

⇒$100 = 20*a$

⇒$a = 5 m/s^{2}$

(b) Final velocity attained by it

We know, $v = u + at$

⇒$v = 0 + 5*5$

⇒$v = 25 m/s$

(c) Distance covered by it

We know, $s = ut + \frac{1}{2} at^{2}$

⇒$s = 0*5 + \frac{1}{2} *5*5^{2}$

⇒$s = 0 + \frac{125}{2}$

⇒$s = 62.5 m$

Hence, the (a) acceleration is $5 m/s^{2}$, (b) final velocity attained is $25 m/s$, and (c) distance covered is $62.5 m$.