Physics, asked by everglistermarngar16, 6 months ago


A force of 100 N gives a body of mass m,, an acceleration of 5 m/s2. The same force can give
an acceleration of 40 m/s2 to another body of mass m2. If both the bodies are tied together and
acted upon by the same force as above, what acceleration is produced in the combination?
14 AA m/s2​

Answers

Answered by ExᴏᴛɪᴄExᴘʟᴏʀᴇƦ
62

Answer

  • The Acceleration Produced when they're tide together would be 4.44 m/s²

Explanation

Given

  • A force of 100 N on a body of mass m¹ produces an acceleration of 5 m/s²
  • The same force on a body of mass m² gives an acceleration of 40 m/s²
  • These two bodies are tied together and the same force is applied

To Find

  • Acceleration Produced?

Solution

● Here we'll use Newton's second law. With that we shall find the masses of the body, add them up as they are tied together and as the same force is applied, simple substitution would give us our answer!!

Mass of Body¹

→ Force = Mass × Acceleration

→ 100 = m × 5

→ 100/5 = m

→ Mass¹ = 20 kg

Mass of Body ²

→ F = ma

→ 100 = m × 40

→ 100/40 = m

→ Mass² = 2.5 kg

Total mass if they were tied together

→ Total Mass = Mass¹ + Mass²

→ Total Mass = 20+2.5

→ Total Mass = 22.5 kg

Acceleration Produced

→ F = ma

→ 100 = 22.5 × a

→ 100/22.5 = a

→ Acceleration = 4.44 m/s²


prince5132: Awesome !!
ItzArchimedes: Splendid !!
Answered by Anonymous
51

Answer:

 \huge  \tt \: required \: answer

 \clubs \sf \: here \: we \: will \: \: apply \: newton \: second \: law

 \huge \fbox {f \:  = ma}

 \sf \: mass \: of \: body \: 1

 \sf \implies \:  100 = m \times 5

 \sf \implies \: 100 = 5m

 \sf \implies \: m =  \frac{100}{5}

 \sf \implies \: m = 20 \: kg

 \sf \: mass \: of \: body 2

 \sf \implies \: 100 = m \times 40

 \sf \implies \: 100 = 40m

 \sf \implies \: m =  \frac{100}{40}

 \sf \implies \: m = 2.5 \: kg

Now, we will find total mass of body

 \sf \: total \: mass \:  = mass1 + mass2

 \sf \implies \: 20 + 2.5

 \sf \implies \: 22.5 \: kg

Now finding acceleration

 \sf \: f \:  = ma

 \sf \implies \: 100 = 22.5 \times a

 \sf \implies \: 100 = 22.5a

 \sf \implies \: 4.444 m/s²

Here,

 \huge \bf \: F = force

 \huge \bf \:  M = mass

 \huge \bf \: A = acceleration


prince5132: Good °_°
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