Question

A force of 100 N is applied perpendicularly at 0.5 m, to turn nut of wheel
of a bus. The torque acting on nut is​

Answer 1

Explanation:

It is very simple if you know the formula,

Torque =force*perp. distance,

Here in your question torque is given in meter whereas distance is in centimeter,so firsh thingh we have to do is convert centimeter into meter during calculation,

Now calculation part,

50=f*30E-2

So, force comes out to be

F=166.67N

Now i am going to tell you somethingh intresting about this question,

Tell me is your mechanics good or bed, to holding only 50Nm torque you required 166.67N force so by seeing it is clear that your mechanics is not good,to make it good mechanics see the torque formula again,

T=f*r

If we want to decrese the force we have to incerese the distance,so change the distance from 30cm to 300cm then calculate,

T=f*r

50=f*300E-2

Now force comes out to be ,

F=16.67N

Now you required only 16.67N force to generate 50Nm torque. This is how mechanics work,to reduce the effort of any mechanics we call it as a mechanical advantage,you will learn this thingh in your higher studies don’t worry

Hope you got your answer

Note-E-2 is 10 to the power (-2) .