Question

a force of 100 N produces an acceleration of 5 m/s^2 on an object. another force 150 N is applied on the same object at rest. the velocity of the object after 6 sec will be what?​

Answer 1

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↪ Given :

Case 1

Force = 100 N

Acceleration = 5m/s^2

Case 2

Force = 150 N

Time = 6 seconds

initial velocity = 0m/s

$\rule{400}{4}$

☆ Required to find :

1. Velocity of the object after 6 seconds .

$\rule{400}{4}$

↦ Explanation :

We can solve this question by using the values obtained in the case 1 .

In case 1 it given that 100 N of force produced an acceleration of 5m/s^2 .

By using the formula ;

$\boxed{\Rightarrow{\boxed{Mass\:= \frac {Force}{Acceleration}}}}$

Above mentioned formula helps us to mass of the object.

In question it is stated that mass is constant .

so using this mass value in 2nd case we can find the acceleration .

Using an formula;

$\boxed{\Rightarrow{\boxed{Acceleration\:= \frac {Force}{Mass}}}}$

Therefore;

Using the first equation of motion and given values we can find the velocity of object after 6 seconds .

The equation is

v = u + at

Here , v = final velocity

u = initial velocity

a = acceleration

t = time

$\rule{400}{4}$

✯ Solution ✯ :

Case 1

Force = 150 N

Acceleration = 5 m/s^2

Mass = ?

Hence ;

Mass = Force / Acceleration

Mass = 100 N / 5 m/s^2

Mass = 20 kgs .

Since, it is given that mass is constant.

Case 2

Mass = 20 kg

Force = 150 N

Acceleration = ?

Acceleration = Force / Mass

Acceleration = 150 N / 20 kg

Acceleration = 7.5 m/s^2

Therefore;

Using the first equation of motion

v = u + at

v = 0 + 7.5 m/s^2 × 6 s

v = 45 m/s

Hence ;

Velocity of the object after 6 sec is 45m/s .

$\rule{400}{4}$

Answer 2

Answer:

\rule{400}{4}

↪ Given :

Case 1

Force = 100 N

Acceleration = 5m/s^2

Case 2

Force = 150 N

Time = 6 seconds

initial velocity = 0m/s

\rule{400}{4}

☆ Required to find :

Velocity of the object after 6 seconds .

\rule{400}{4}

↦ Explanation :

We can solve this question by using the values obtained in the case 1 .

In case 1 it given that 100 N of force produced an acceleration of 5m/s^2 .

By using the formula ;

\boxed{\Rightarrow{\boxed{Mass\:= \frac {Force}{Acceleration}}}}

⇒

Mass=

Acceleration

Force

Above mentioned formula helps us to mass of the object.

In question it is stated that mass is constant .

so using this mass value in 2nd case we can find the acceleration .

Using an formula;

\boxed{\Rightarrow{\boxed{Acceleration\:= \frac {Force}{Mass}}}}

⇒

Acceleration=

Mass

Force

Therefore;

Using the first equation of motion and given values we can find the velocity of object after 6 seconds .

The equation is

v = u + at

Here , v = final velocity

u = initial velocity

a = acceleration

t = time

\rule{400}{4}

✯ Solution ✯ :

Case 1

Force = 150 N

Acceleration = 5 m/s^2

Mass = ?

Hence ;

Mass = Force / Acceleration

Mass = 100 N / 5 m/s^2

Mass = 20 kgs .

Since, it is given that mass is constant.

Case 2

Mass = 20 kg

Force = 150 N

Acceleration = ?

Acceleration = Force / Mass

Acceleration = 150 N / 20 kg

Acceleration = 7.5 m/s^2

Therefore;

Using the first equation of motion

v = u + at

v = 0 + 7.5 m/s^2 × 6 s

v = 45 m/s

Hence ;

Velocity of the object after 6 sec is 45m/s .

\rule{400}{4}