A force of 100 newton acts on an object of mass 10 kg for 9 sec. If the object was initially moving with the speed of 10 m/s, calculate the initial and final kinetic energy of the object. By what factor does the kinetic energy increase?
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initial kinetic energy= ½mu²
so ½ ×10× 10²= 500 j
f = ma
a= f/m
a= 100/10
a= 10m/s²
v=u+at
v=10+ 10(9)
v= 100m/s
final kinetic energy= ½mv²
= ½×10×(100)²
=5000 j
Sannidhya:
You missed out this:By what factor does the kinetic energy increase?
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