Question

A force of 100N acts on an area of 50cm2. What is the magnitude of pressure in pascal?

Answer 1

GIVEN,

$thrust = 100n \\ area = 50cm ^{2}$

TO FIND,

$pressure$

SOLUTION,

$pressure = \frac{thrust}{area} \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \frac{100n}{50cm ^{2} } \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \frac{2n}{cm ^{2} } \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 2n \: \: cm ^{ - 2} = 2 \: pascal$

Therefore pressure= 2 Pascal

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Answer 2

Given,

• Force = 100N
• Area = 50cm^2

To Find:-

Magnitude of pressure in pascal.

Formula used:-

Pressure = Force / Area

Calculations:-

Pressure = Force / Area

Now substituting the given values:

$= \frac{100}{50 {cm}^{2} }$

$= 2n \: {cm }^{ - 2}$

Magnitude of pressure in pascal is 2pascal.