Physics, asked by thelotagroup, 3 months ago


A force of 100N acts on an object of mass 10kg for 9 sec. If the object was initially moving with the speed
of 10m/sec, calculate the initial and final kinetic energy of the object.

Answers

Answered by Adityasinghh3006
0

F=100N

M=10Kg

A=10 T=9

V=?

V=U+AT

V=10+10*9

V=100M/S^2

KINETIC ENERGY=1/2MV^2

=1/210*100*100

=50000N

Answered by Stevi
0

Answer:

Acceleration = \frac{Force }{mass}

                     = \frac{100}{10}

                     = 10 m/s²

Final velocity v = u + at

                         = 10 + (10 × 9)

                         = 100 m/s

Initial kinetic energy  = \frac{1}{2}mu^2

                                    = 5 × 10 × 10

                                    = 500 J

Final kinetic energy  = \frac{1}{2} mv^2

                                 = 5 × 100 × 100

                                 = 50000 J

Change in Kinectic energy = Final kinetic energy - Initial kinetic energy

                                             = 50000 - 500

                                             = 49500 J

                                             = 49.5 KJ

                      Hope it helps you^_^

Similar questions