Question

A force of 100n is applied horizontally to a block weighing 10kg friction is 0.5 find accelatation

Answer 1

Answer:

5 m/s^2

Explanation:

let F be applied force 100N

f be force of friction i.e 0.5*10*10=50 N

then

F-f=m*a

100-50 = 10*a

a=5 m/s^2