Question

A force of 100N is applied tangentially to a wheel of

dimeter 0.4 m , calculate the torque about the centre of the

wheel​

Answer 1

Answer:

torque about centre of the wheel is 20N-m

Explanation:

Given :- f = 100N

diameter = 0.4 and radius 'r'= 0.2

angle θ = 90° (tangentially)

As we know that, torque τ = r×f = rfsinθ

• ∴ 0.2× 100× sin90° ∵ (sin90° = 1)
• => 20N-m Answer.

Answer 2

Answer:

60N -M

Explanation:

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