A force of 100N is applied tangentially to a wheel of
dimeter 0.4 m , calculate the torque about the centre of the
wheel
Answers
Answered by
7
Answer:
torque about centre of the wheel is 20N-m
Explanation:
Given :- f = 100N
diameter = 0.4 and radius 'r'= 0.2
angle θ = 90° (tangentially)
As we know that, torque τ = r×f = rfsinθ
- ∴ 0.2× 100× sin90° ∵ (sin90° = 1)
- => 20N-m Answer.
Answered by
0
Answer:
60N -M
Explanation:
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