Question

a force of 100N produces a change of 0.1% in a length of wire of area of cross section 1mm^2 calculate Young's modulus of wire​

Answer 1

Young's modulus will be equal to $10^{11}N/m^2$

Explanation:

We have given force F = 100 N

Change in length is 0.1%

Area of cross section $A=11mm^2=10^{-6}m^2$

Let the length of the wire is l

Change in length $\Delta l=l\times \frac{0.1}{100}=10^{-3}l$

So strain $\frac{\Delta l}{l}=\frac{10^{-3}l}{l}=10^{-3}$

Stress $=\frac{force}{area}=\frac{100}{10^{-6}}=10^8N/m^2$

Young's modulus is equal to $\gamma =\frac{stress}{strain}=\frac{10^8}{10^{-3}}=10^{11}N/m^2$

So young's modulus will be equal to $10^{11}N/m^2$

Learn more

Calculate the force required to produce an elongation of 0.1 cm in a steel wire of radius 1mm and length 2m.( Youngs modulus of the wire = 20×10^10 N/m^2).

https://brainly.in/question/14204336

Answer 2

Answer:10^11N/m2

Explanation: