Question

A force of 10n acting on a particle increases it's velocity from 15 m/s to 19 m/s in 2 s. the mass of the particle is​

Answer 1

Explanation:

a=

Δt

Δv

=

2

6−5

=0.5ms

−2

F=ma

∴m=

a

F

=

0.5

0.6

=1.2kg

Answer 2

Since, F=ma F=Force, a=acceleration

m=mass

$a = \frac{v - u}{t}$

PUT THE VALUE OF (a) in [F=Ma]

$f = \frac{m(v - u)}{t}$

v= final velocity

u= initial velocity

t= time taken

$10 = m \frac{19 - 15}{2}$

10 = 2m

therefore, [m=5 kg]