A force of 10N acts for 20s on a body of mass 2kg initially at rest. Calculate the energy required by the body and the work done by the applied force.
Answers
Answered by
2
Answer:
10KJ
Explanation:
F = ma
F = m x (v-u)/t
Ft = mv - mu
10x20 = 2(v) - m(0)
200/2 = v
100m/s = v
ΔKE = Work Done
1/2mv² - 1/2mu² = W
1/2(2)(100)² - 1/2(2)(0)² = W
10000 - 0 = W
10000J = W
10kJ = W
Kindly mark me as brainliest.
Similar questions